A/S Level Pure Maths Help please
#31
![Post](images/icons/icon1.gif)
All of which has bugger all to do with helping solve the original Q.
I certainly dont remember any Euclidian maths in Further Maths A level let alone A/S perhaps you could answer the original question without resorting to the shortcuts you remember.
Surely you can prove these theories from first principles (which it pretty much seems the question is effectively asking you to do?)
Deano
I certainly dont remember any Euclidian maths in Further Maths A level let alone A/S perhaps you could answer the original question without resorting to the shortcuts you remember.
Surely you can prove these theories from first principles (which it pretty much seems the question is effectively asking you to do?)
Deano
#32
![Post](images/icons/icon1.gif)
In fact I've just got those answers just via basic geometry.
My method which I'm sure is hopelessly inefficient...
I used A=0,0 B=10,0 C=10,10 D=0,10
Consider just two of the interecting arcs. e.g. Arc centred on A (0,0) and Arc Centred on B. (10,0). Call the point of intersection E. We can Calculate its co-ords. as (5,8.660) using basic pythag.
Also intersection of Arc onA and arc centered on D is Point F (8.660,5)
Calulate the length EF (5.177) and the angle made (30degress as we now know) via more basic trig.
So perimeter of shaded area is now 4 times the length of the arc on 30degress - formula given.
Area is our Length EF^2 + 4x areas of segment whose chord is EF. I looked up the formula for area of a segment but you could easily do (area of sector AEF) - (area of triangle AEF). Area of Segment = 1.180. Making total area 31.5 to 3sf.
All of which takes far far less time to do than to type![Wink](images/smilies/wink.gif)
Deano
My method which I'm sure is hopelessly inefficient...
I used A=0,0 B=10,0 C=10,10 D=0,10
Consider just two of the interecting arcs. e.g. Arc centred on A (0,0) and Arc Centred on B. (10,0). Call the point of intersection E. We can Calculate its co-ords. as (5,8.660) using basic pythag.
Also intersection of Arc onA and arc centered on D is Point F (8.660,5)
Calulate the length EF (5.177) and the angle made (30degress as we now know) via more basic trig.
So perimeter of shaded area is now 4 times the length of the arc on 30degress - formula given.
Area is our Length EF^2 + 4x areas of segment whose chord is EF. I looked up the formula for area of a segment but you could easily do (area of sector AEF) - (area of triangle AEF). Area of Segment = 1.180. Making total area 31.5 to 3sf.
All of which takes far far less time to do than to type
![Wink](images/smilies/wink.gif)
Deano
#33
![Talking](images/icons/icon10.gif)
Deano comes out tops again ![Big Grin](images/smilies/biggrin.gif)
http://www.scoobynet.co.uk/bbs/threa...ThreadID=52741
Thanks very much![Cool](images/smilies/cool.gif)
P.S. Luckily it didnt come up in the exam
![Big Grin](images/smilies/biggrin.gif)
http://www.scoobynet.co.uk/bbs/threa...ThreadID=52741
Thanks very much
![Cool](images/smilies/cool.gif)
P.S. Luckily it didnt come up in the exam
![Wink](images/smilies/wink.gif)
#34
![Post](images/icons/icon1.gif)
![Big Grin](images/smilies/biggrin.gif)
![Wink](images/smilies/wink.gif)
It makes a nice break from swearing about bits of cisco kit that refuse to do what it says on the tin.
![Roll Eyes (Sarcastic)](images/smilies/rolleyes.gif)
I used to enjoy maths and it frustrates me that I've forgotten so much of it
![Smile](images/smilies/smile.gif)
Deano
Do you keep a record of all your old maths threads
![Embarrassment](images/smilies/redface.gif)
![Wink](images/smilies/wink.gif)
#36
![Wink](images/icons/icon12.gif)
For those numpties amongst us...
I bow at the feet of such collective genii...
Mak (the Dim)
Q. for you clever s0ds...
How many pints of strong Cider are required to get the average Essex Blonde in the sack? No catches, no hidden facts - just plain old calculus.
I bow at the feet of such collective genii...
Mak (the Dim)
Q. for you clever s0ds...
How many pints of strong Cider are required to get the average Essex Blonde in the sack? No catches, no hidden facts - just plain old calculus.
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